Question

How do you graph the function `f(x) = 2/3x + 490`?

Answer 1

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For `x = 0`

`f(0) = (2/3 xx 0) + 490`

`f(0) = 0 + 490`

`f(0) = 490` or `(0, 490)`

Second Point: For `x = -300`

`f(-300) = (2/3 xx -300) + 490`

`f(-300) = -200 + 490`

`f(-300) = 290` or `(-300, 290)`

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-490)^2-500)((x+300)^2+(y-290)^2-500)=0 [-1200, 1200, -600, 600]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-(2/3)x-490)(x^2+(y-490)^2-500)((x+300)^2+(y-290)^2-500)=0 [-1200, 1200, -600, 600]}