Question #a81aa
1 Answer
See explanation.
Explanation:
The value in the interval
#x in <0;2pi># is#pi/2# ,#sinx# takes#-1# and#1# only once in each period, so the general solution is:
#x=pi/2 + 2kpi; k in ZZ#
See explanation.
The value in the interval
#x in <0;2pi># is#pi/2# ,#sinx# takes#-1# and#1# only once in each period, so the general solution is:
#x=pi/2 + 2kpi; k in ZZ#