How do you evaluate #\sqrt{(-6)^{2}}-4(-3)(4)#?

1 Answer
Tamir E.
Nov 15, 2017

#sqrt((-6)^2)-4*(-3)*(4)=54#

Explanation:

First:
#(-6)^2=36#
#sqrt((-6)^2)=sqrt(36)=6#

Second:
#-4*(-3)*(4)= # negative 4 times negative 3 is positive 12
#=> (+12)(+4)=# positive 12 times positive 4 is 12+12+12+12=48
#=> -4*(-3)*(+4)=48#

third:
#sqrt((-6)^2)-4*(-3)*(4)=#
#=> 6+48=54#

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