Which quadrants and axes does #f(x)=x-sqrt(x+5)# pass through?

1 Answer
Nov 15, 2017

#I#, #III# and #IV# quadrants and it passes through y-axis at #(0,-sqrt(5))# and x-axis at #(sqrt(21)/2+1/2,0)#.

Explanation:

graph{x-sqrt(x+5) [-6.407, 7.64, -5.67, 1.356]}

As you can see the graph passes through #I#, #III# and #IV# quadrants.

To know the y-axis point you have to substitute de #x# by #0#. So:
#f(x)=x-sqrt(x+5) ➝ f(0)=0-sqrt(0+5)=-sqrt(5)≈-2.236#
And you get the point #(0,-sqrt(5))#.

To know the x-axis point(s) you have to equal the function to #0#. So:
#f(x)=x-sqrt(x+5)=0#
you isolate the variable #x#:
#x=sqrt(21)/2+1/2≈2.79#
So you get the point #(sqrt(21)/2+1/2,0)#.