How do you graph #f(x) = 3sqrtx + 2 #?
1 Answer
You take a few critical points, and graph.
Explanation:
Normally we choose the Y-intercept (when x=0) and the X-intercept (when y=0), and x=1, x=-1, x=2, etc. Close values to zero.
Let's calculate the y-intercept first.
x=0
3
y-intercept
y=0
0=3
-2=3
x=1
3
x=-1
3
of a negative number does not exist.
Pretty soon we can see that the graph will start AFTER zero and nothing before. Then it will be a curve low to high as it progresses right. Graph below:
graph{3sqrt(x)+2 [-10, 10, -5, 5]}