Simplify this index law question?

(2xy)22(x2y)38(xy)3

1 Answer
Nov 16, 2017

(2xy)22(x2y)38(xy)3=x5y2

Explanation:

Laws:
(xy)a=xaya
(xa)b=xab
xaxb=xa+b
xaxb=xab


(2xy)22(x2y)38(xy)3
=(2)2x2y22x23y38x3y3
=4x2y22x6y38x3y3
=(42)(x2x6)(y2y3)8x3y3
=(8)(x2+6)(y2+3)8x3y3
=(8)(x8)(y5)8x3y3
=(88)(x8x3)(y5y3)
=(1)(x83)(y53)
=(x5)(y2)
=x5y2