Question

How do you find the asymptotes for `f (x ) = (3x^2 - 2x - 1) / (x + 4 )`?

Answer 1

Vertical asymptote `x=-4`

Explanation:

`3x^2-2x-1`
`x_(1,2)=(2+-sqrt(4-4*3*(-1)))/(2*3)=(2+-4)/6`
`=>`
`x_1=1`
`x_2=-1/3`
`=>`
`f_((x))=((x-1)(3x+1))/(x+4)`
`=>`
Vertical asymptote `x=-4`