How do you solve #-2x+4=x-8#?

1 Answer
Jim G.
Nov 17, 2017

#x=12#

Explanation:

#"collect terms in x on the left side of the equation"#
#"and numeric values on the right side"#

#"subtract "x" from both sides"#

#2x-x+4=cancel(x)cancel(-x)-8#

#rArrx+4=-8#

#"subtract 4 from both sides"#

#xcancel(+4)cancel(-4)=-8-4#

#rArrx=-12" is the solution"#

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