A ball with a mass of #200 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #12 (kg)/s^2# and was compressed by #3/5 m# when the ball was released. How high will the ball go?

Question

2546 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-18T09:13:14

The height is #=1.1m#

enter image source here

The spring constant is #k=12kgs^-2#

The compression is #x=3/5m#

The potential energy is

#PE=1/2*12*(3/5)^2=2.16J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

Mass of the ball is #m=0.2kg#

#PE_(ball)=2.16=0.200*9.8*h#

#h=2.16*1/(0.200*9.8)#

#=1.1m#

The height is #=1.1m#