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Answer 1 · 2017-11-18T11:44:16

This uses the momentum equation, #F.t = m Deltav# and assumes that force remains constant throughout the interaction.

Incidentally, this equation is just a rearramhDeltangement of Newton’s 2nd law, and we’ll use it in the form #F = m(Delta v)/(Delta t)#

#F = 0.1 xx (50 - 0)/(5 xx 10^-3)#

#F = 1000# N

Answer 2 · 2017-11-18T11:49:35

Average acceleration #bara=(Deltav)/t#
where #Deltav=#change in speed, and #t=#time

#bara=(50.0m//s)/(5.00*10^(-3)s)=1.00*10^4m//s^2#

Since average force #barF=m*bara#

#barF=0.100kg*1.00*10^4m//s^2=1.00*10^3kg*m//s^2=1.00*10^3N#
as #N-=kg*m//s^2# by definition