How do you solve this system of equations: #x+ y + z = 8 and x - y - z = - 4 and x - y + z = 0#?

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Answer 1 · 2017-11-19T00:18:24

#x=2#, #y=4#, #z=2#

Given:

#{(x+y+z=8),(x-y-z=-4),(x-y+z=0):}#

Adding the first two equations together, we get:

#2x = 4#

So:

#x = 2#

Subtracting the second equation from the third equation, we get:

#2z = 4#

So:

#z = 2#

Then from the first equation:

#y = 8 - x - z = 8 - 2 - 2 = 4#