How do you evaluate (12+ 28- 4) \div 6+ 3^ { 2}(12+284)÷6+32?

1 Answer
Nov 19, 2017

1515

Explanation:

Laws:
1) First "()", Second power/sqrtroot, Third times or divided, Forth plus or minus.
2) evaluate from left to right.
3) x^2=x*xx2=xx


First:
"()"
=> (12+28-4)=(40-4)=36(12+284)=(404)=36

Second:
"power"
=> 3^2=3*3=932=33=9

Third:
"divided"
=> (12+28-4):6=36:6=6(12+284):6=36:6=6

Forth:
"plus"
=>(12+28-4):6+3^2=6+9=15(12+284):6+32=6+9=15