How do you evaluate #0.25 - 1/5 x + 4xy# if #x = 45# and # y = 1/5#?
1 Answer
Nov 19, 2017
Explanation:
#"substitute the given values for x and y into the expression"#
#0.25-(1/cancel(5)^1xxcancel(45)^9)+(4xxcancel(45)^9xx1/cancel(5)^1)#
#=0.25-9+36#
#=27.25#
