Question #048a8

1 Answer
Nov 19, 2017

1

Explanation:

#sin(a)=-(sqrt(65)/65)#

Get the arcsine

#A=sin^-1(-sqrt(65)/65)#

#A=-7.125^o#

But angle A is on quadrant III

Get coterminal angle

#360-7.125=352.875#

Get reference angle

#360-352.875=7.125#

Get angle on Quadrant III

#180+7.125=187.125#

Test A if derived angle is correct

#sin(-7.125)=-0.124#
#sin(187.125)=-0.124#

Use angle A for half angle identity of cosine

#cos(A/2)##= sqrt((1+cos(187.125))/2)#

Resulting to

=#0.998 ~= 1 #