How do you divide ( -3x^3+ 16x^2-24x+9 )/(x + 1 )?
2 Answers
Nov 19, 2017
Explanation:
If we descompose
Nov 19, 2017
Explanation:
"one way is to use the divisor as a factor in the numerator"
"consider the numerator"
color(red)(-3x^2)(x+1)color(magenta)(+3x^2)+16x^2-24x+9
=color(red)(-3x^2)(x+1)color(red)(+19x)(x+1)color(magenta)(-19x)-24x+9
=color(red)(-3x^2)(x+1)color(red)(+19x)(x+1)color(red)(-43)(x+1)color(magenta)(+43)+9
=color(red)(-3x^2)(x+1)color(red)(+19x)(x+1)color(red)(-43)(x+1)+52
"quotient "=color(red)(-3x^2+19x-43)," remainder "=52
rArr(-3x^3+16x^2-24x+9)/(x+1)
=-3x^2+19x-43+52/(x+1)