Question #b6de6

1 Answer
Dani W.
Nov 19, 2017

#f''=-4pi^2z^2cos(piz^2)-2pisin(piz^2)#

Explanation:

Find #f'# through differentiation.
#f'=-sin(piz^2)*2piz#

Find #f"# by differentiating #f'#.
#f''=(-cos(piz^2)*2piz*2piz)+(2pi*-sin(piz^2))#

#f''=-4pi^2z^2cos(piz^2)-2pisin(piz^2)#

Related questions
Impact of this question
796 views around the world
You can reuse this answer
Creative Commons License