How do you evaluate #\sqrt{5^{2}+31}-16#?

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Answer 1 · 2017-11-20T06:06:39

#sqrt(5^2+31)-16=color(blue)(2sqrt14-16#

Simplify.

#sqrt(5^2+31)-16#

Simplify #5^2# to #25#.

#sqrt(25+31)-16#

Simplify.

#sqrt(56)-16#

Prime factorize #56#.

#sqrt((2xx2)xx2xx7)-16#

Simplify.

#2sqrt14-16#