Given the first term and the common dimerence er an arithmetic sequence how do you find the 52nd term and the explicit formula: #a_1=25, d=6#?
1 Answer
Nov 20, 2017
Explanation:
#"the nth term of an arithmetic sequence is "#
#•color(white)(x)a_n=a+(n-1)d#
#"where a is the first term and d the common difference"#
#"here "a=a_1=25" and "d=6#
#rArra_n=25+6(n-1)#
#color(white)(rArra_n)=25+6n-6#
#rArra_n=6n+19#
#rArra_(52)=(6xx52)+19=331#