Question

Question #57c64

Answer 1

18 ways

Explanation:

For this problem, since the 3 clients must sit together, and there are 5 available seats, there are only 3 ways that they can be seated:

X X X - -, - X X X -, - - X X X

However, within the group of 3 seats together (which I showed as Xs above), there are 3! ways to seat the people in those seats.

Thus, there are `(3)(3!) = 3*6 = 18` ways to arrange the seating.