Question

How I can predict the group and from following configuration? 6s2, 5d1, 4f3 .

Answer 1

See the answer below....

Explanation:

There is a rule to predict the group and period of an element by its ELECTRONIC CONFIGURATION...

For S Block elements:-

• Last electronic configuration:- `color(red)(n"S"^(1-2)` where `n=1,2,3...`
• Group of the element:- `(color(green)(1-2))` for `S^1` is `1` and for `S^2` is `2`.
• Period:-the value of `color(red)(n`

For P Block elements:-

• Last electronic configuration:- `color(red)(n"S"^2n"P"^(1-6))` where `n=1,2,3...`
• Group of the element:- 1) for `color(red)(n=1`, group is `color(red)(13`
  `color(white)(QQQQQQQQQQQhhhhhhdQ`2) for `color(red)(n=2`, group is `color(red)(14`
  `color(white)(QQQQQQQQQQQhhhhhhdQ`3) for `color(red)(n=3`, group is `color(red)(15`
  `color(white)(QQQQQQQQQQQhhhhhhdQ`4) for `color(red)(n=4`, group is `color(red)(16`
  `color(white)(QQQQQQQQQQQhhhhhhdQ`5) for `color(red)(n=5`, group is `color(red)(17`
  `color(white)(QQQQQQQQQQQhhhhhhdQ`6) for `color(red)(n=6`, group is `color(red)(18`
• Period:-the value of `color(red)(n`

For D Block elements:-

• Last electronic configuration:- `color(red)((n-1)"D"^(1-10)n"S"^(2 or, 1` where `n=1,2,3...`
• Group of the element:-
  `color(white)(QQQQQQQQQQQhhhhhdQ`1) for `color(red)(n=1`, group is `color(red)3`
  `color(white)(QQQQQQQQQQQhhhhhdQ`2) for `color(red)(n=2`, group is `color(red)(4`
  `color(white)(QQQQQQQQQQQhhhhhdQ`3) for `color(red)(n=3`, group is `color(red)(5`
  `color(white)(QQQQQQQQQQQhhhhhdQ`4) for `color(red)(n=4`, group is `color(red)(6`
  `color(white)(QQQQQQQQQQQhhhhhdQ`5) for `color(red)(n=5`, group is `color(red)(7`
  `color(white)(QQQQQQQQQQQhhhhhdQ`6) for `color(red)(n=6`, group is `color(red)(8`
  `color(white)(QQQQQQQQQQQhhhhhdQ`7) for `color(red)(n=7`, group is `color(red)(9`
  `color(white)(QQQQQQQQQQQhhhhhdQ`8) for `color(red)(n=8`, group is `color(red)(10`
  `color(white)(QQQQQQQQQQQhhhhhdQ`9) for `color(red)(n=9`, group is `color(red)(11`
  `color(white)(QQQQQQQQQQQhhhhhdQ`10) for `color(red)(n=10`, group is `color(red)(12`
• Period:-the value of `color(red)(n`

For F Block elements:-

• Last electronic configuration:- `color(red)((n-2)"F"^(1-14)(n-1)"D"^(0-1)n"S"^2` where `n=1,2,3...`
• Group of the element:- always `color(red)(3` because these elements are inner transitional elements...
• Period of the element:- the value of `color(red)(n`

Hope it helps...
Thank you...

Answer 2

See the rules I have written...
Let's answer...

Explanation:

`6"S"^2 5"D"^1" 4F"^3` is an `F` block element which has a electronic configuration of `F` block element. It is of `color(red)(3` no. group..

Hope it helps...
Thank you...