Question

Question #f6f50

Answer 1

Binary operation in `RR^n` Field

Explanation:

Let `x,y in RR^n`
`=>`
`(a+b)*c = a*(b+c) = a*c+b*c` Distributive property
`a+b=b+a` Commutative property
`EE2_F 1_F+1_F=2_F`

`(x+y)(x+y)=x(x+y)+y(x*y)` Distributive property
`x(x+y)+y(x*y)=x*x+x*y+y*x+y*y` Distributive property
`x*x+x*y+y*x+y*y=x*x+x*y+x*y+y*y` Commutative property
`x*x+x*y+x*y+y*y=x*x+2*x*y+y*y` `EE2_F`