How do you solve #15=\frac{m}{3}-6#?

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Answer 1 · 2017-11-22T02:17:29

See a solution process below:

First, add #color(red)(6)# to each side of the equation to isolate the #m# term while keeping the equation balanced:

#15 + color(red)(6) = m/3 - 6 + color(red)(6)#

#21 = m/3 - 0#

#21 = m/3#

Now, multiply each side of the equation by #color(red)(3)# to solve for #m# while keeping the equation balanced:

#color(red)(3) xx 21 = color(red)(3) xx m/3#

#63 = cancel(color(red)(3)) xx m/color(red)(cancel(color(black)(3)))#

#63 = m#

#m = 63#