Question

How do you graph (4, -1/2), (1/5, 5) on the coordinate plane?

Answer 1

See a solution process below:

Explanation:

To plot the point `(4, -1/2)` we need to go 5 units to the right on the `x` axis and then `1/2` unit down on the `y` axis giving:

graph{((x - 4)^2 + (y + 0.5)^2 - 0.05) = 0 [-5, 15, -2, 8]}

To plot the point `(1/5, 5)` we need to go 1/5 of a unit to the right on the `x` axis and then `5` units up on the `y` axis giving:

graph{((x - 0.2)^2 + (y - 5)^2 - 0.05 )((x - 4)^2 + (y + 0.5)^2 - 0.05) = 0 [-5, 15, -2, 8]}