Question

Question #457c7?

Answer 1

Jason had 84 $ and Wilson had 91 $

Explanation:

Let Jason have 12x $ and Wilson 13x$. After spending 63$ , he will have 13x-63 $ with him.

The situation now is that 12x $ is 3 times of (13x-63)$. Putting it in equation form, it would be
12x= 3* (13x-63) `->` 12x= 39x-189`->` 27x=189 `->` x=7

This means that at the beginning Jason had 84$ and Wilson had #91$
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Answer 2

Wilson originally had $91

I have taken you to a point where you should be able to finish off.

Explanation:

`color(blue)("Setting up the given information")`

Let Jason's original money be represented by `j`
Let Wilson's original money be represented by `w`

Using ratio in fraction format

Then initial condition

`j/w=12/13 color(white)("ddd")->color(white)("ddd") j=12/13w" ".........Equation(1)`

But Wilson spent $63 changing the ratio to:

`j/(w-63)=3/1color(white)("ddd")->color(white)("ddd")j=3w-189" "..Equation(2)`

Using `Eqn(2)` substitute for `j" in "Eqn(1)`

`color(green)(color(red)(j) =12/13wcolor(white)("ddd")->color(white)("ddd")color(red)(3w-189)=12/13w )`

`color(green)(color(white)("dddddddddd")->color(white)("ddd")27/13w=189)`

`color(white)("dddddddddd")->color(white)("dddddd")color(blue)(w=$91)`
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Substitute for `w` in `Equation(1)` to find Jason's original sum of money.