Question #9cca0

1 Answer
Evan Holbrook
Nov 22, 2017

22.4L

Explanation:

At standard temperature and pressure (0 Celsius and 1.00 atm) 1 mol of an ideal gas will occupy 22.4L.

This can be seen in this equation by solving for V:

#PV = nRT# where P is pressure in atm, V is volume in L, n is the number of moles, R is the gas constant 0.08206 #L*atm#, and T is the temperature in Kelvin. Let's plug in STP for 1 mol of gas:

#1.00*V = (1.00*R*273)#

#1.00*V = 22.4#

Thus, #V=22.4#

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