Question

Question #9cca0

Answer 1

22.4L

Explanation:

At standard temperature and pressure (0 Celsius and 1.00 atm) 1 mol of an ideal gas will occupy 22.4L.

This can be seen in this equation by solving for V:

`PV = nRT` where P is pressure in atm, V is volume in L, n is the number of moles, R is the gas constant 0.08206 `L*atm`, and T is the temperature in Kelvin. Let's plug in STP for 1 mol of gas:

`1.00*V = (1.00*R*273)`

`1.00*V = 22.4`

Thus, `V=22.4`