Question

Question #78c95

Answer 1

The original number is `83`.

Explanation:

Let the digit at tenth place be `x` and at unit place be `y`.

So, the number in algebraic form is `10x+y`.

From the first condition

`y=x/2-1=(x-2)/2`.......(i)

From second condition

`10y+x=3(x+y)+5`

or, `10y+x=3x+3y+5`

or, `7y=2x+5`

Putting the value of `y` from (i) we get

`7((x-2)/2)=2x+5`

or, `7x-14=4x+10`

or, `3x=24`

or, `x=24/3=8`

Putting the value of `x` in (i) we get

`y=(x-2)/2=(8-2)/2=3`

Now `10x+y=10*8+3=83`

So the required number is `83`.