Question

How do you simplify `\frac { 3v ^ { 2} + 20v + 25} { 3v + 5}`?

Answer 1

`(v+5)`

Explanation:

Factor the numerator first, so:
`(3v^2+20v+25)/(3v+5)=((3v+5)(v+5))/(3v+5)`

Cross out the common `(3v+5)` to get:
`(v+5)`

So simplification of the equation si `(v+5)`