How do you graph #f(x)=(2x^3+x^2-8x-4)/(x^2-3x+2)# using holes, vertical and horizontal asymptotes, x and y intercepts?
1 Answer
Nov 27, 2017
see below
Explanation:
hole:
vertical asymptote:
horizontal asymptotes:
graph{(2x^3+x^2-8x-4)/(x^2-3x+2) [-200, 200, -150, 150]}