What is the vertex form of y=(-x-2)(x+5)?

1 Answer
Nov 28, 2017

y=-(x+7/2)^2+9/4

Explanation:

y=-x^2-5x-2x-10
y=-x^2-7x-10
To make it look more 'pretty': y=-(x^2+7x+10)
Now we need to make it into Vertex Form!
y=-(x+7/2)^2+9/4
Let's check by solving it.
y=-(x+7/2)^2+9/4 =
-(x^2+7x+49/4)+9/4 =
-x^2-7x-49/4+9/4 =
-x^2-7x-10
That gets us back to our question. Therefore, we are correct!

YAY!