How do you evaluate #\frac { 74} { 8} \times \frac { 1} { 9}#?

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Answer 1 · 2017-11-28T05:21:05

#37/36#

#74/8 xx1/9#

#= cancel74^37/cancel8^4 xx1/9" "larr #simplify using the HCF #2#

#=37/36" "larr# multiply straight across.

OR, multiply straight across first:

#(74xx1)/(8xx9)#

#=74/72" "larr# divide top and bottom by #2# (HCF)

#=37/36#