How do you evaluate #(- 5) ^ { 3} - [ ( - 6) \cdot \{ ( - 5) - 2}]#?

1 Answer
Nov 29, 2017

-167

Explanation:

Follow BEDMAS (bracket, exponents, division, multiply, addition, subtraction)

Find exponent first

#=(-5)^3 - [(-6)*{(-5)-2}] #

Solve subtraction within the inner bracket

#=(-125) - [(-6)*{(-5)-2}] #

Multiply inner bracket

#=(-125) - [(-6)*{-7}] #

Subtract

#=(-125) - [42] #

#=-167#