How do you evaluate #(- 5) ^ { 3} - [ ( - 6) \cdot \{ ( - 5) - 2}]#?

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Answer 1 · 2017-11-29T01:59:24

-167

Follow BEDMAS (bracket, exponents, division, multiply, addition, subtraction)

Find exponent first

#=(-5)^3 - [(-6)*{(-5)-2}] #

Solve subtraction within the inner bracket

#=(-125) - [(-6)*{(-5)-2}] #

Multiply inner bracket

#=(-125) - [(-6)*{-7}] #

Subtract

#=(-125) - [42] #

#=-167#