Question

Question #71224

Answer 1

There are no solutions

Explanation:

equation 1: `xy = 1441`
equation 2: `x + y = -2` -

rearrange equation 2
equation 3: `y = -2 -x`

substitute for `y` in equation 1 using the value from equation 3
`x(-2-x) = 1441`

simplify
`-x^2 -2x = 1441`

rearrange
`0 = x^2 +2x+ 1441`

we now have a quadratic in the form `y = ax^2 +bx + c`

calculate the discriminant using
`b^2 -4ac`

substitute in what we know
`2^2 - 4*1*1441 = -5760`

The discriminant is negative so the equation has no real roots
Therefore the original pair of equations do not intersect