Question #71224

1 Answer
Nov 29, 2017

There are no solutions

Explanation:

equation 1: xy = 1441
equation 2: x + y = -2 -

rearrange equation 2
equation 3: y = -2 -x

substitute for y in equation 1 using the value from equation 3
x(-2-x) = 1441

simplify
-x^2 -2x = 1441

rearrange
0 = x^2 +2x+ 1441

we now have a quadratic in the form y = ax^2 +bx + c

calculate the discriminant using
b^2 -4ac

substitute in what we know
2^2 - 4*1*1441 = -5760

The discriminant is negative so the equation has no real roots
Therefore the original pair of equations do not intersect