How do you divide #( x^4-2x^3-8x+16 )/(4x-6)#?

1 Answer
Barney V.
Nov 30, 2017

#1/4x^3-1/8x^2-3/16x-2 9/32#and remainder of #29 11/16#

Explanation:

#(x^4-2x^3-8x+16)/(4x-6)#

#color(white)(..........)color(white)(.)1/4x^3-1/8x^2-3/16x-2 9/32#
#4x-6|overline(x^4-2x^3+0x-8x+16)#
#color(white)(.............)ul(x^4-3/2x^3)#
#color(white)(................)-1/2x^3+0x#
#color(white)(..................)ul(-1/2x^3+3/4x^2)#
#color(white)(...........................)-3/4x^2-8x#
#color(white)(............................)ul(-3/4x^2+9/8x)#
#color(white)(....................................)-73/8x+16#
#color(white)(.....................................)ul(-73/8x-438/32)#
#color(white)(....................................................)950/32=29 11/16#

#(x^4-2x^3-8x+16) / (4x-6) =1/ 4x^3-1/8x^2-3/16x-2 9/32#and remainder of#29 11/16#

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