How do you solve #\frac { x ^ { 2} } { x + 10} - \frac { 10} { x + 10} = 0#?

1 Answer
Dec 1, 2017

#x= sqrt(10) = 3.16#;

#x = -sqrt(10) = -3.16#

Explanation:

We have the equation:

#(x^2/(x+10)) - (10/(x+10)) = 0#

Left-hand side of the equation (LHS) is

#=(x^2/(x+10)) - (10/(x+10))#

To simplify LHS, take the common denominator which is #(x + 10)#

We get

#=(x^2 - 10)/(x+10)#

Now our equation becomes

# (x^2 - 10)/(x+10) = 0#

We can rewrite this equation as

# (x^2 - 10)/(x+10) = 0/0#

Multiply both sides by #(x+10)# to get

# (x + 10)(x^2 - 10)/(x+10) = (0/0)x+10#

#rArr x^2 - 10 = 0 " " color(red)(Equation.1)#

We can write 10 as #[ sqrt(10 )]^2#

Hence our #color(red)(Equation.1)# becomes

#rArr x^2 - (sqrt(10))^2 = 0 " " color(red)(Equation.2)#

We are now ready to use the factoring formula :

#(x^2 - y^2) = (x+y)(x-y) #

Now we can rewrite the #color(red)(Equation.2)# using our factoring formula as

#(x + sqrt(10)) (x - sqrt(10)) = 0 " " color(red)(Equation.3)#

We can get the factors as

#(x + sqrt(10)) =0 or (x - sqrt(10)) = 0#

#rArr x = -sqrt(10) or x = +sqrt(10)#

We get

#x= sqrt(10) = 3.16#;

#x = -sqrt(10) = -3.16#

I hope this is useful.