If #(x/3 +1, y - 2/3) = (5/3, 1/3)#, what is the values of #x# and #y#?

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Answer 1 · 2017-12-03T01:58:16

#x=2\quad,\quad y=3#

This can be broken up into two equations:

#\frac{x}{3}+1=\frac{5}{3}#

#y-\frac{2}{3}=\frac{1}[3}#

Solving the first one:

#\frac{x}{3}=\frac{2}{3}#

#\implies x=3\cdot\frac{2}[3}#

#\implies x=2#

Solving the second one:

#y=\frac{2}{3}+\frac{1}{3}#

#\implies y=3#