Question

Question #e3c50

Answer 1

`y'=-10sinx*cos^9x`

Explanation:

We can rewrite `y=cos^10x` as follows:

`y=cos^10x->y=(cosx)^10`

Differentiating

`y'=10(cosx)^9*d/dx(cosx)`

`y'=10(cosx)^9*-sinx`

`y'=-10sinx*cos^9x`