Question #e7dd8

1 Answer
Dec 4, 2017

4.76 mL

Explanation:

The molar mass of H_2SO_3=82.01gmol^(-1)

Molar number of H_2SO_3=(0.0351 g)/(82.01gmol^(-1))=4.28xx10^(-4)mol

Molarity of H_2SO_3=S1=4.28xx10^(-4)molxx1000ml1/(250ml)=1.712xx10^(-3)M

Reaction:

H_2SO_3+2NaOH->Na_2SO_3+2H_2O
1mole of H_2SO_3 reacts with 2 mole NaOH.
Suppose,

S1=Molarity of H_2SO_3=1.712xx10^(-3)M,V1=Volume of

H_2SO_3=250 mL

S2=Molarity of NaOH=.18M,V2=Volume of NaOH=?

((S1V1)(H_2SO_3))/((S2V2)(NaOH))=1/2

=)V2=(2S1V1)/(S2)=4.76 mL