Could you do this for me?
2 Answers
This is what I think
Explanation:
Look at the coordinates of maximum in the graph
Coordinates of maximum in the new graph
Comparing both we observe that in the new graph
Now look at the coordinates of minimum in the graph
Coordinates of minimum in the new graph
Comparing both we observe again that in the new graph
These points are easy to locate.
For any value added to
For any value subtracted from
In case of
For any value added to
For any value subtracted from
Note the difference of sign in
As such all points on graph
Hence option (E)
Explanation:
#"consider the coordinates of the stationary points"#
#"max at "(0,1)to" max at "(1,3)#
#"min at "(2,-1)to" min at "(3,1)#
#"both have been translated by "((1),(2))#
#f(xcolor(red)(-1))color(magenta)(+2)" describes"#
#f(x)" translated 1 unit to the right and 2 units vertically"#
#color(blue)"in general"#
#f(x+a)" movement of a units left"larr#
#f(x-a)" movement of a units right "rarr#
#f(x)+a" movement vertically up of a units "uarr#
#f(x)-a" movement vertically down of a units" darr#