How to solve cos(x)+sin(x) > 0?
3 Answers
See the answer below...
Explanation:
We know that ,
" " color(red)(sin^2x+cos^2x=1 Let's use the inequality here.....
sin^2x+cos^2x=1
=>(sinx+cosx)^2-2cdot sinx cdot cosx=1
=>(sinx+cosx)^2=1+2 cdot sinx cdot cosx
[The value ofcolor(red)(2 cdot sinx cdot cosx might becolor(red)(0) butcolor(red)(1>0 ]
=>(sinx+cosx)^2>0
=>sinx +cosx>0 Hope it helps...
Thank you...
Explanation:
and
making now
we get
Explanation:
sin x + cos x > 0
Use trig identity:
On the unit circle, cos (x - pi/4) > 0 --> 2 solutions:
a. the arc
b. The arc
Answers by intervals: