How do you evaluate #6^ { - 1} \cdot 5^ { - 2} #?

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Answer 1 · 2017-12-06T03:46:31

See a solution process below:

Use this rule of exponents to rewrite each term in the expression:

#x^color(red)(a) = 1/x^color(red)(-a)#

#6^color(red)(-1) * 5^color(red)(-2) =>#

#1/6^color(red)(- -1) * 1/5^color(red)(- -2) =>#

#1/6^color(red)(1) * 1/5^color(red)(2) =>#

#1/6 * 1/25 =>#

#(1 * 1)/(6 * 25) =>#

#1/150#