Question

Question #738f7

Answer 1

`24 " minutes"`

Explanation:

`lcm(6,8) = 24`
(least common multiple)
`lcm(a,b) = (a*b)/gcd(a,b)`
`=> lcm(8,6) = (8*6)/gcd(8,6)`
`and gcd(8,6) = gcd(6,2) = 2`
`"because" gcd(a,b) = gcd(a-b, b) if a > b`
(greatest common divisor)
`=> lcm(8,6) = 48/2 = 24`

Answer 2

We need to calculate LCM of the two given timings: `6and8` min.

factors of `6->ul2xx3`
factors of `8->ul2xx2xx2`
LCM`=2xx3xx2xx2` (`ul2` is included once)
LCM`=24` min