How do you find the center and radius of the circle given #(x-sqrt5)^2+y^2-8y=9#?

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Answer 1 · 2017-12-06T12:40:19

Centre : # (sqrt5 ,4)# and radius: #5# unit

The center-radius form of the circle equation is

#(x – h)^2 + (y – k)^2 = r^2# with at the point #(h, k)#

and the radius being #r#.

#(x-sqrt5)^2 +y^2-8y =9 # or

#(x-sqrt5)^2 +y^2-8y+16 =9+16 # or

#(x-sqrt5)^2 +(y-4)^2 =5^2 #

#:. h= sqrt5 , k= 4 and r=5#

Therefore centre is at # (sqrt5 ,4)# and radius is #5# unit [Ans]