How do you evaluate #2^{2}+4\times 2+3#?

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Answer 1 · 2017-12-06T16:02:29

#15#

Follow BEDMAS (Bracket, exponent, division, multiplication, addition, subtraction)

Since your equation does not have any brackets, let’s move and solve the exponents.
Note: I bracketed the parts you need to focus on.

#[2^2]+4*2+3 = 4+4*2+3#

Following BEDMAS, there is no division, but there is multiplication, so we have to solve that next.

#4+[4*2]+3 = 4+ 8+3#

And finally, we add everything together.

#[4+8+3]=15#