Find the value of limit sin(x^2+4x)/(x^3-5x^2+2x) as x approaches to 0?
1 Answer
Dec 6, 2017
Explanation:
Note that:
Do the division:
# = (x(x+4)-9(x+4)+38)/(x+4) = x-9+38/(x+4)#
to see that
Now we have
# = sin(x^2+4x)/((x^2+4x)) * 1/(x-9+38/(x+4))#
As
# = 1 * 1/(0-9+38/(0+4))#
# = 1/(-9+17/2) = 1/(1/2) = 2#