Question #e61aa
2 Answers
Q1:
Explanation:
Integrals can be solved in many ways, but for these I'll be using trig-substitution for Q1 and partial fractions for Q2.
Q1:
For this, we want to make use of the fact that
So, instead of just using
Let
Even though we've done the integration, we have to change it back into terms of
This leaves us with
Also,
Therefore, subbing it into the achieved result we get:
Q2:
Q1 is below all of this
Explanation:
Q2:
First, we break up the fraction inside:
To do this, we can multiply both sides by
Then to solve for
Sub in
Sub in
Therefore, we see that:
We will use this in our integration:
Recognize that each of the fractions is a