Question #59d74

1 Answer
Dec 8, 2017

#6m# though some values of #m# will have a LCM of #n6m, ninZZ#

Explanation:

We first split the two numbers into their prime factors.

#12=2xx2xx3#
#3m=3xxm#

#12# has 3 factors, while #3m# has two factors.

An LCM must be divisible by both numbers. So we will take all facotrs while leaving out any duplicates:

#2xx2xx2xx3xx3xxm#

#LCM=2xx3xxm=6m# (Though some numbers will be a multiple of #6m#)

A graph can be found here: https://www.desmos.com/calculator/gdv8vbn9ed