How do you solve #.5\times (\frac{13\pi }{4})^{2}#?

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Answer 1 · 2017-12-09T13:24:25

It can be simplified to #(169π^2)/32#.

We can convert 0.5 into a fraction for convenience:

#1/2 * ((13π)/4)^2#

Square both the numerator and the denominator:

#1/2 * ((13π)^2)/4^2#

#1/2 * (169π^2)/16#

Multiply:

#(169π^2)/32#

That's as far as we can go without evaluating #π#.