Question

How do you simplify `\frac { ( a ^ { 4} b c ^ { 2} ) ( 3a ^ { 4} b ^ { 3} c ^ { 2} ) ^ { 2} } { ( 3a ^ { 3} b ^ { 3} c ^ { 2} ) ^ {3} }`?

Answer 1

the simplified form is `1/3a^3/b^2`

Explanation:

given `[(a^4bc^2)(3a^4b^3c^2)^2]/(3a^3b^3c^2)^3rArr[(a^4bc^2)(9a^8b^6c^4)]/(27a^9b^9c^6)`

`rArr[9a^(8+4).b^(6+1).c^(4+2)]/(27a^9b^9c^6)rArr(a^12.b^7c^6)/(3a^9b^9c^6)rArr1/3[a^(12-9).b^(7-9).c^(6-6)]`

`rArr1/3a^3/b^2`