Question #d9b17

1 Answer
Dec 10, 2017

x<-4," and " x> -1

Explanation:

Plotting the graph:
As x^2+5x+4=0 factorises as (x+4)(x+1) the x intercepts are at y= -1" and" -4.
Y-intercept is at x= 4
Coefficient is 1 so normal out 1 up 1 parabola)
Hence:
graph{x^2+5x+4 [-7, 3, -5, 10]}

Now your question is for an inequality not an equation, so the answer is the area of the graph which is bigger than zero.

So this is everywhere above the x-axis:
graph{(x^2+5x+4)>0 [-7, 3, -5, 10]}

:. x<-4, x> -1