Question

How do you divide #(6x^3-16x^2+17x-6) / (3x-2) # using polynomial long division?

Answer 1

Quotient: `2x^2-4x+3` and remainder: `0`

Explanation:

`6x^3-16x^2+17x-6`

=`6x^3-4x^2-12x^2+8x+9x-6`

=`2x^2*(3x-2)-4x*(3x-2)+3*(3x-2)`

=`(2x^2-4x+3)*(3x-2)`

Quotient: `2x^2-4x+3` and remainder: `0`